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diff --git a/pd/doc/3.audio.examples/J05.triangle.pd b/pd/doc/3.audio.examples/J05.triangle.pd
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+#X coords 0 0.5 881 -0.5 200 130 1;
+#X restore 382 119 graph;
+#X text 381 257 ---- 0.02 seconds ----;
+#X text 350 505 updated for Pd version 0.39;
+#X obj 46 242 output~;
+#X obj 140 276 tabwrite~ \$0-sum;
+#X obj 130 107 / 100;
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+#X obj 206 108 / 100;
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+1;
+#X obj 151 250 metro 193;
+#X obj 19 95 phasor~;
+#X floatatom 19 74 5 0 0 0 - - -;
+#X text 11 51 frequency;
+#X text 126 50 SLOPES (percent);
+#X obj 108 137 *~;
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+#X obj 19 154 +~ 1;
+#X obj 184 156 *~;
+#X obj 108 189 min~;
+#X text 341 118 0.5;
+#X text 338 237 -0.5;
+#X text 30 4 Making waveforms with corners by specifying line segment
+slopes;
+#X text 136 67 up;
+#X text 209 68 down;
+#X text 29 317 Occasionally a second method for making corners is more
+convenient. Here we specify the slopes of the rising and falling segments
+(as always \, in units per cycle). We then make a triangle wave with
+a corner at (0 \, 0) and another one \, placed somewhere within the
+cycle. The slopes of the two lines determine the second point \, which
+will have an x value of t/(s+t) (if we let s denote the rising slope
+and t the falling one \, both as positive numbers). The y value is
+st/(s+t). If we wish instead to specify the corner location (x \, y)
+(with x in cycles \, 0<x<1) we set s = y/x and t = y/(1-x). The DC
+value is y/2.;
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